Subject: Nutritionists/Docs shocked

From: DrOz Carb Blockers <[email-masked]>
Date: Thu, 05 Jun 2014 13:06:13 -0700

Dr.Oz begs the question:
"Did you know you can get your body to stop absorbing carbs?"

Studies have shown, your ideal entire carb-intake for one day equals to 1 baked potato (or 100 grams).
This is unrealistic for most Americans, and Dr Oz has realized this. 

- Now, for the first time DrOz is presenting the "Carb Blocker" -
- Enjoy pasta, bread, pizza w/out absorbing the carbs

View Here: / http://www.ecuchoir.com/Oz/carb/blocker.video

It will have you losing 230% More... W/Out the gym.

-DrOz Summer Blog

We hope that you enjoyed this wellness notification.
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the scene or learn the rules or think big thoughts about what kind of person would be the right person for me when I walked into a bar 11 years ago and met this guy for a drink. Nevertheless, if you were to try isolate a single trait essential in a life partnership, I think you should look for a person who is pro-whim  that is, encourages you to have whims and pursue them, for better or for worse. Does that sound too abstract? Okay, fine; let me propose instead the Strawberry Rhubarb Pie Bar Test, which should be enlisted as follows. 1. Find a potential mate. 2. Say, Do I need to good reason to make strawberry-rhubarb pie bars? 3. If they answer, as mine did on Monday, Nope. I think theyre always welcome they do not have the common prefix the checking of \1 after the \0 separator always fails at the first character": Oh, good point. But the worst case is still at least O(n): suppose that the strings both have length n, and their common prefix has length n/2. Then you have to try n/2 
 possible \1s, and each try examines n/2 characters before it fails. O(n/4) = O(nujii9u7h import re
u9oh pattern = re.compile("(?P<prefix>\S*)\S*\s+(?P=prefix)")
v8uyovpattermatch("stack stable")group('prefix')pattern.match("123456 12345").group('prefix')'12345' That's still at least O(n). The worst-case time occurs when $first and $second are identical: the engine then needs to test every single prefix of $first. If a prefix has length m, then testing for it is at least O(m), so the worst-case time is at least O(0+1+2+...+n), which is O(n).  	  	
(Also, that would misbehave slightly if $second starts with $first followed by a space, since then \2 would always match, so (?!\2) would never succeed. But that's remediable either by using \0 again instead of a space -- since, by assumption, $second doesn't contain \0 -- or else by saying that the longest common prefix is $1 // $first rather than simply $1.It is true that i did not count with the fact, that the prefix as it gets longer gets rechecked everytime from beginning. But it should not be necessary - it can just check the letters which it is adding, but I do not know how to put it in one regexp.(No, you are not right, and Yes the cornercase is annoying :-) The double \0's, did not work when I tried it fast, so i introduced the space, which works I believe. If the $second starts with $first and space, than if would not match, because if \2 eats \0 and the \0 can not match. )   gorn Feb 2 '12 at 20:05
  	  	
(Yeah, with \0\0 you need to tweak it a bit further, because otherwise the (.*?) can have length zero, and the \0\1(?!\2) will then match the first \0, because (?=\0) implies (?!\2). I think that changing \0\1(?!\2) to \0(?!\0)\1(?!\2) would suffice. named entities tend to be the most robust way of handling non-ASCII characters. For any document that might end up out of your control -- copied to a different computer, served by who-knows-what server with unknown settings, emailed a couple dozen times, etc. -- using html entities is pretty much the only way to ensure that somebody down the line doesn't get utter gibbe