Subject: Results speak for themselves - We tell all

From: Fast Weight-Loss Results <[email-masked]>
Date: Thu, 05 Jun 2014 07:46:33 -0700

Oz Show: Lose 30 in 30 can it be done easily?

The simple answer to that question is "YES".

I know a lost of you don't have the time to spend every waking moment in the gym. Well neither do I. You probably have a vacation coming up and would like to look like your old self again.

http://www.thelispiece.com/yahoo-432/LB-loss/today/i673-hsf.hhtml

NOTE: This is not another workout video or calorie counting starvation session. It's as easy as saying 1-2-3.

What's up in the celeb world?
Dig Into a Dish from Hugh Jackmans Go-To Lunch Spot

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Angelina Jolie's Birthday Wish: 'My Family to Remain Healthy'

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Randy Travis Steps Out for Friend Dolly Partons Concert

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1.	In a large bowl, mix together 1/3 cup condensed French onion soup with ground beef, bread crumbs, egg, salt and black pepper. Shape into 6 oval patties.
2.	In a large skillet over medium-high heat, brown both sides of patties. Pour off excess fat.
3.	In a small bowl, blend flour and remaining soup until smooth. Mix in ketchup, water, Worcestershire sauce and mustard powder. Pour over meat in skillet. Cover, and cook for 20 minutes, stirring occasionally.

Noticed a line in our codebase today which I thought surely would have failed the build with syntax error, but tests were passing so apparently it was actually valid python (in both 2.x and 3).

Whitespace is sometimes not required in the conditional expression:

>>> 1if True else 0
1
It doesn't work if the LHS is a variable:

>>> x = 1
>>> xif True else 0
  File "<stdin>", line 1
    xif True else 0
           ^
SyntaxError: invalid syntax
But it does seem to still work with other types of literals:

>>> {'hello'}if False else 'potato'
'potato'

The Python lexer generates two tokens for the input 1if: the integer 1 and the keyword if, since no token that begins with a digit can contain the string if. xif, on the other hand, is recognized as a valid identifier; there is no reason to believe that it is an identifier followed by a keyword, and so is passed to the parser as a single token.