Subject: Were clearing 2014's to make room

From: Very Low Priced 2014's <[email-masked]>
Date: Fri, 13 Jun 2014 14:14:12 -0700

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In the Spring XML file, there's a PropertyPlaceholderConfigurer defined:

I want to inject one of the properties from app.properites into the bean shown above. I can't simply do something like

Because PersonDaoImpl does not feature in the Spring XML file (it is picked up from the classpath via annotations). I've got as far as the following:

@Repository("personDao")
public class PersonDaoImpl extends AbstractDaoImpl implements PersonDao {

@Resource(name = "propertyConfigurer")
protected void setProperties(PropertyPlaceholderConfigurer ppc) {
// Now how do I access results.max?
}
}

But it's not clear to me how I access the property I'm interested in from ppc?
Is systemProperties simply System.getProperties()? I guess if I want to inject my own properties into a Spring bean I need to define a then read values from that into another bean using something like @Value("#{appProperties.databaseName}") Don Apr 6 '11 at 20:50
7
Make sure to note from max's answer that you can also use placeholders in the expressions ${db.doStuff}, then you don't need a PropertiesFactoryBean, just a placeholderConfigurer gtrak Jul 21 '11 at 0:15
6
You can add your own properties using util:properties; e.g., . See the edited answer for how to get the value. (I realize this is probably too late to have been helpful to Don, but others will hopefully benefit.) Willie Wheeler Jan 28 '12 at 19:34
2
It only worked for me when I used util:properties in my appname-servlet.xml file. Using propertyConfigurer defined in my applicationContext.xml (not the Spring MVC one) didn't work

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AppServlet
org.springframework.web.servlet.DispatcherServlet

contextConfigLocation
WEB-INF

namespace
application-context.xml

1

OK, first let's get some important moment clear. There are two types of contexts we are dealing with:

root context(parent)

individual servlet context(child)

Quote from the Spring Framework API (at the moment of writing 3.2.2) for thmphasis mine):

Like generic application contexts, web application contexts are hierarchical.There is a single root context per application, while each servlet in the application (including a dispatcher servlet in the MVC framework) has its own child context.

Also here:

For example, if you are developing a Spring MVC web application you will typically have aroot WebApplicationContext loaded via Spring's ContextLoaderListenerand achild WebApplicationContext loaded via Spring's DispatcherServlet. This results in a parent-child context hierarchy where shared components and infrastructure configuration are declared in the root context and consumed in the child context by web-specific components.

And here:

home
dog
two
face
cow
tunnel
back
zone-1
come

ApplicationContext instances in Spring can be scoped. In the Web MVC framework,each DispatcherServlet has its own WebApplicationContext, which inherits all the beans already defined in the root WebApplicationContext. These inherited beans can be overridden in the servlet-specific scope, and you can define new scope-specific beans local to a given Servlet instance.

The namespace is essentially an alternative way of telling Spring container context loader class what config file to use. I never bother with it, but just use contextConfigLocation whenever I need to configure custom config files.

Local-GGR Auto __ 141 Barren Rd __ Newton Square __ PA __ 1.9.0.7.3 __Rem oval __ Prefs__

What's the proper way to create a hyperlink in Spring+JSP? There must be a better way than just coding in the tag. Take for example a page that displays people. The URL is people.htm. The corresponding controller gets people from the database and performs optional column sorting. The JSP might look like:

import org.springframework. beans.factory.BeanFactoryUtils;
import org springframework. context.support.AbstractApplicationContext;
import org. springframework. cont ext.support.ClassPathXml ApplicationContext;